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Nnesha (nnesha):
again similar right triangle
Nnesha (nnesha):
oh nvm you're working on num 2
OpenStudy (anonymous):
no the 1st one too
OpenStudy (anonymous):
i think 2 is 3sqr root 3
Nnesha (nnesha):
one question per post
let me know when u r done with number 2 :=))
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OpenStudy (anonymous):
ill tag you i guess
OpenStudy (anonymous):
ookay
OpenStudy (rccb):
sorry im not sure the first one
Nnesha (nnesha):
alright tag me when u finish #2
OpenStudy (anonymous):
@RCCB for #2 its 3sqr. root 3 right?
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OpenStudy (rccb):
yeah that's the answer i kept getting
OpenStudy (anonymous):
okay thank you (:
OpenStudy (anonymous):
@Nnesha okay #2 is done ready for #1? (:
Nnesha (nnesha):
|dw:1445983259327:dw|
there are two triangles
small one and the big triangle
OpenStudy (anonymous):
okay i see it
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OpenStudy (anonymous):
how do we set up the problem?
Nnesha (nnesha):
separate themm |dw:1445983644106:dw|
here is given hypotenuse and the length of both triangle
for this question you need to remember ` HL:LS ` rule
\[\rm \frac{ H }{ L } =\frac{ L }{ S }\]
first fraction is for smaller triangle