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The figure below shows a rectangle ABCD having diagonals AC and DB: Jimmy wrote the following proof to show that the diagonals of rectangle ABCD are congruent: Jimmy's proof: Statement 1: In triangle ADC and BCD, AD = BC (opposite sides of a rectangle are congruent) Statement 2: Angle ADC = Angle BCD (angles of a rectangle are 90°) Statement 3: Statement 4: Triangle ADC and BCD are congruent (by SAS postulate) Statement 5: AC = BD (by CPCTC) Which statement below completes Jimmy's proof? AB=AB (reflexive property of equality) AB=AB (transitive property of equality) DC=DC (reflexive property of equality) DC=DC (transitive property of equality)
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