Question

for the simple harmonic equation d=5sin(2pi) what is the period?

Answer 1

I beleive B=0. Unless This is science. I'm not good with science.

Answer 2

its kinda science and what are you meaning by b? this is precalculus

Answer 3

I think the period is just 2pi.. but I feel like there is a way that I am supposed to calculate it

Answer 4

Is there a variable missing on the right hand side? Cause this just says\[d=5\sin2 \pi = 5(0) = 0\]

Answer 5

oh yeah! d=5sin(2pi t)

Answer 6

I've attached the graph of this function. It should help.