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find the equation of the parabola given the vertex is (2,-3) and the focus is (6,-3)
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subtract the vertex to move everything to the origin ... then use what you know from there and then move it back
|dw:1445994362072:dw|so im thinking since the vertex is (2,-3) and the parabola is in the form x=y^2
4px' = y'^2 given that x',y' is an adjustment from teh origin yes
|dw:1445994630522:dw|
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