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@xMissAlyCatx
\(\large\color{black}{ \displaystyle {\rm Cos}(a-b)= {\rm Cos}(a) {\rm Cos}(b)+ {\rm Sin}(a) {\rm Sin}(b) }\) (this rule can be also proven - geometrically) Therefore: \(\large\color{black}{ \displaystyle {\rm Cos}(\theta-\theta)= {\rm Cos}\theta{~}{\rm Cos}\theta+ {\rm Sin}\theta{~}{\rm Sin}\theta }\) \(\large\color{black}{ \displaystyle {\rm Cos}(0)= {\rm Cos}^2\theta+ {\rm Sin}^2\theta }\) \(\large\color{blue}{ \displaystyle1= {\rm Cos}^2\theta+ {\rm Sin}^2\theta }\)
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