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Evaluate loga24 using the fact that loga2 = 0.4307 and loga3 = 0.6826
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use the fact that \(24=2^3\times 3\)
so you want \[\log(2^3\times 3)\] then use the properties of the log to expand this as a sum and product of logs
step one is \[\log(2^3\times 3)=\log(2^3)+\log(3)\] since \[\log(AB)=\log(A)+\log(B)\] always
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