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Trigonometry 8 Online
OpenStudy (anonymous):

prove csc(A-B)=sin(A+B)/sin^2A-sin^2B

OpenStudy (anonymous):

please help i tried starting on the left but all i got was 1/sin(A-B) and then it goes to 1/sinAcosB-cosAsinB

Directrix (directrix):

Grouping symbols would be helpful for me because I am unsure of what portion of the problem appears in the denominator. Which of these, if either, is the statement to be proved? @1clarissa |dw:1446103721635:dw|

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