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OpenStudy (dan815):
how many 1 factors does a W_n have? There are no 1 factors when n is even right, the way the question asks, kinda looks like theres a formula just based on n, and not in cases... but i just want to confirm there really are no 1 factors existing when n is even right, because no odd path length can possible have a 1factor, as it takes 2 vertices for a 1 factor, and an odd number of vertices cannot results in a 1 factor decomposition
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OpenStudy (dan815):
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