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Solve x^3 = -1
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\[x^3=-1\] \[x=\sqrt[3]{-1}\] \[x=-1\]
check: x^3=-1 (-1)^3=-1 -1=-1 correct
There's two answers. Would it be -1 and 1+/-i(sqrt3) over 2?
not completely.\[x^3 + 1 = 0\]\[\Rightarrow (x+1)(x^2 - x + 1) = 0\]\[\Rightarrow x = -1, \frac{1\pm i\sqrt{3} }{2}\]
exactly^^
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Thank you both!
yeah i forgot of the second answer
hey could somone here help me with my question when yall are done?
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