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Algebra
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FIND THE DIFERECNCE 9 4 ------ minus ----- 3x 2x^2 3x 2x2
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HI!!
i sthis \[\frac{9}{3x}-\frac{4}{2x^2}\]?
yeah
then lcd is \(6x^2\)
you can do \[\frac{9\times 2x-4\times 3}{6x^2}\]
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i dont know how to solve
\[18x -12 \over 5x ^{2}\]
it's 18x-12 over 6x^2 so yoou can simplify by 6 and you get 3x-2 over ....
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