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how many two digit numbers are divisible by either 3 or 5
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10, 12, 15, 18, 20, 21, 24, 25, 27, 30, 33, 35, 36, 39, 40, 42, 45, 48, 50, 51, 54, 55, 57, 60, 63, 65, 66, 69, 70, 72, 75, 78, 80, 81, 84, 85, 87, 90, 93, 95, 96, 99. 42 all together I think
Use the inclusion/exclusion principle: Let A = set of 2-digit numbers divisible by 3 B = set of 2-digit numbers divisible by 5 A\(\cap\)B = set of 2-digit numbers divisible by 15 (i.e. by 3 and by 5) and apply the following rule: \(|A\cup B|=|A|+|B|-|A\cap B|\) where |A| = number of elements in set A = cardinality of A
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