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$$ 10\ge7+3x \text{ and } 9-4x\le1 $$ Let rewrite: $$ \cfrac{10-7}{3}\ge x\\ x\le \cfrac{10-7}{3} $$ Can you work on the second inequality in the same manner?
The result will be something like this - https://www.desmos.com/calculator/qfbn06cts3
Okay thats cool! Awesome
If you click on where the blue and the red line intersect the x-axis - that will be your answer $$ 9-4x\le1\\ -4x\le1-9=-8\\ x\ge\cfrac{-8}{-4}=2 $$ So the answer is $$ x\ge 2\text{ and }x\le \cfrac{10-7}{3}=1 $$
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Okay sweet!! Thanks so much!
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