Question

Solve for x:
4^x - 6(2^x) + 8 = 0

Answer 1

\[\left( 2^2 \right)^x-6*2^x+8=0\]

Answer 2

put\[2^x=t\]
squaring
\[\left( 2^x \right)^2=t^2\]
solve the quadratic for t

Answer 3

i have missed some steps.You solve in detail.