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How do you rewrite x^2+9 as multiplication using complex numbers and the polynomial u^2+v^2=(u+vi)(u-vi)
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plug into the formula you were given
example x^2+4=(x+2i)(x-2i
So x^2+9=(x+3i)(x+3i)?
Wait it would be (x+3i)(x-3i)
\[x^2+9=x^2-\left( -9 \right)=x^2-\left( 3\iota \right)^2=?\]
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So I was right?
yes (x+3i)(x-3i) is correct
Awesome thank you!
np
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