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Use the Law of Cosines and find side b. Is it 15.38?
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|dw:1446440694757:dw| a = 29, c = 39, and theta is 20 degs
is this a right triangle?
No
nvm was thinking something else...let me check
just substitute and calculate the value...
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you mean c^2=
I used the formula...my answer is in the question
oops \[b^2 = a^2 + c^2 - 2ac \cos(\theta)\]
so then you have \[b^2 = 29^2 + 39^2 - 2 \times 29 \times 39 \times \cos(20)\]
or you can just google a triangle solver, put in what you know and check your answer that way
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I also got 15.38
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