Question

The sum of three consecutive even integers is -72. What is the least of these numbers?
-26
-22
-30
24

Answer 1

Are you sure those are the answers?

Answer 2

let x be 1 even integer

what is the next one..?

Answer 3

Nevermind I read it wrong

Answer 4

Think as the consecutive numbers as this (x+1)+(x+2)+(x+3)= -72
Solve the equation and then find x
So would look like this
3x+6=-72
3x=-78
x= -78/3

Answer 5

Read my previous post and x would be your answer

Answer 6

Because the consecutive numbers have to be even so you would have to do x + (x + 2) + (x + 4) because then you would be getting all consecutive even numbers.

Answer 7

Sorry I am wrong they are supposed to be even listen to Lexie

Answer 8

are you sure x is the answer... remember you have

x, x+2 and x + 4

Answer 9

Isn't "least" referring to greatest negative value?

Answer 10

@denonakavro we are doing even consecutive so x is even
and count by 2's ( x-2, x, x + 2 )

Answer 11

x + (x +2) + (x + 4) = -72; afterwards you would add all the xs together and add the numbers and get 3x + 6 = -72 then afterwards you would subtract 6 from both sides and end up with 3x = -78 then you would divide 3 on both sides and end with x = -26 but that is the greatest factor like @jaeuni had said so you would have to take -26 and add 4 to it