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Find the period of f(x) = sin(1/2)x
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\[f(x)= \sin \frac{ 1 }{ 2 }x\] Isn't this just \[\frac{ 1 }{ 2 }\]
|dw:1446448819060:dw|
its \(\frac{2\pi}{1/2}\)
you understand how to find time period?
I do, but \[ \frac{ 2\pi }{ 1/2 }\] isn't an option.
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is \(4\pi\) an option?
@sloppycanada
\( 2\pi \div 1/2 =2\pi \times 2\)
Yes @baru Sorry, someone was at the door.
What is the period of the function f(x)= cos2x? This is just \[\frac{ 1 }{ 2 }\pi\] Correct?
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its \(2\pi/2\)
Again, not an option... So, 4 again?
\(2 \pi/2=\pi\)
if ur function is \[Asin(\omega x)\] time period \[T=\frac{2\pi }{\omega}\]
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