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a=3 b=-1 c=-10 use this to find the second solution of this equation -b-the square root of b^2-4ac all divided by 2a
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The quadratic formula \[\huge~\rm~x=\frac{ -(-1) \pm \sqrt{(-1)^2-4(3)(-10)} }{ 2-(10) }\]
The quadratic formula \[\huge~\rm~x=\frac{ 1 \pm \sqrt{(-1)^2-4(3)(-10)} }{ 2-(10) }\]
Simplyfy
a=3 not 10
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