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Mathematics 21 Online
OpenStudy (anonymous):

120m^16/45m^8 8b^3/20b^3 For this question I believe the answer is either 2/5b or 2/5, not sure though :/

OpenStudy (tkhunny):

You should get to grouping and factoring. You'll need this: \(\dfrac{a^{m}}{a^{n}} = a^{m-n}\)

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