Question

help:


What is the general form of the equation for the given circle?




x2 + y2 − 8x − 8y + 23 = 0




x2 + y2 − 8x − 8y + 32 = 0




x2 + y2 − 4x − 4y + 23 = 0




x2 + y2 + 4x + 4y + 9 = 0

Answer 1

http://cdn.ple.platoweb.com/PCAP-ASSETS-PROD/03974c930e3e47c78f1614a92ab2c070

Answer 2

@undeadknight26 @Deadly_Roses @GabeBae

Answer 3

What is this?

Answer 4

hmmm. is this even math?

Answer 5

@GabeBae

Answer 6

yes its a Math question that I don't get at all

Answer 7

If this has something to do with circles. What grade are you?

Answer 8

if you could answer that?

Answer 9

ok do you know how to complete a square?

Answer 10

(x^2 -8x _) + y^2- 8y _) +23=0

Answer 11

take the first equation in your answers and separate the terms like this

(x^2 -8x _) + y^2- 8y _) +23=0

now half the middle term and sqaure it like this
1/2)(-8) = -4 and (-4)^2 = 16,

x and y are the same,
remember we are adding 16 onthe left twice--so we must add it on the right twice,so

(x^2 -8x+16) + (y^2- 8y+16) +23=16+16

now factor the x nad y trinomial into squares

what do you get??

Answer 12

can you factor them??