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4(x-3)+5x=-48 A.-4 B.all real numbers C.0 D.4
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@vera_ewing
So first, distribute 4(x-3) That would end up as: 4x-12
So then, you have to isolate the variable, which is x.
why did you have to swich the 12 and the 5?
4x - 12 + 5x = -48 4x + 5x - 12 = -48 4x + 5x - 12 + 12 = -48 +12 4x + 5x = -36 9x = -36 x = -4
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Ok, so I switched the 12 and the 5 because we have to get all of the x's on the right side.
ooh okay lol sorry im a bit slow lmao
It's ok! :-)
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