medal and fan awaiting Adrienne had a party at a local skating rink. She spent one hundred dollars for a party room and eight dollars per person for skates. Let c be the total cost of the room and skates, and let f be the number of friends at her party. Write an equation to represent the problem. Which is the independent variable? Explain
Do you know which variables to apply to what numbers And can you define Independent variables vs. Dependent variables?
I will help you with this, as long as you work along with me. If you do not know something, I will explain to you, okay?
i dont know anything about this
Okay, let me help.
Adrienne had a party at a local skating rink. She spent one hundred dollars for a party room and eight dollars per person for skates. Let c be the total cost of the room and skates, and let f be the number of friends at her party. Write an equation to represent the problem. Which is the independent variable? Explain c=total cost f=number of friends at the party. 100+8f=c This is the equation we have to help solve.
a variable (often denoted by x ) whose variation does not depend on that of another.
a variable (often denoted by y ) whose value depends on that of another.
i dont get it
'c', the cost would be your dependent variable, because it depends on 100 and 8f
Your 'f' variable should be the independent variable.
That number controls what c will be, since 100 is already given and paid for.
i still dont under stand it
What don't you understand?
oh nvm i didnt read it correctly
Does everything make sense then?
yes f is the independent variable because it doesnt rely on 100 and 8f
Well, 8f is part of 'f' but you basically got the right idea. In a way, you could say that 'f' is the independent because thats the variable we can control. Basically when you throw the party, you control how many people you want to come. But you cannot control the cost.
so the answer is "'f' is the independent because thats the variable we can control"
Yep.
We can 'manipulate' it.
thank you so much
Anytime, I will help anytime.
Join our real-time social learning platform and learn together with your friends!