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solve the equation 3r^2+2r-8=0
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\[3(r^2+(2/3)r)-8=0\]
\[3(r^2+(3/2)r/2)-8=0\]
\[3(r^2+3/2r+(3/4)^2)-8=0\]
\[3(r^2+3/2r+9/16)-27/16-8=0\]
\[3(r+3/4)^2-155/16=0\]
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\[3(r+3/4)^2=155/16\]
\[(r+3/4)^2=\frac{ 155 }{ 16 }/3\]
\[(r+3/4)^2=155/48\]
\[r+3/4=\sqrt{(\frac{ 155 }{ 48 })}\]
\[r=\pm \sqrt{465}/12-3/4\]
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