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find the solution set 7x^2+6x-1=0
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Do you know the quadratic formula, it is the best way
can you show me how?
x=1/7,−1
ax^2+bx+c=0 then x={-b+sqrt(b*b-4a*c)}/2a and x={-b-sqrt(b*b-4a*c)}/2a
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then plug in the a value, b value, and c value and you should get the answers -1, and 1/7
7x*x+6x-1=0 7x*x+(7-1)x-1=0 7x*x+7x-x-1=0 7x(x+1)-1(x+1)=0 (x+1)(7x-1)=0
thanks for the help yall
Who medaled zach, it is not even allowed to give direct answers by code of conduct
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