Question

tan2θ - sec2θ = _____

Answer 1

tan 2x-sec 2x
=sin 2x/cos 2x - 1/cos 2x

Answer 2

what do ido next

Answer 3

take LCM

Answer 4

and use sin 2x=2 sin x cos x
1=sin^2 x +cos ^2 x
and cos 2x =cos^2x - sin ^2 x

Answer 5

(sin 2x-1)/cos 2x

Answer 6

now is that my answer