Question

find the zeroes of the function. h(x)=x^2+23x+60

Answer 1

x^2+23x+60
Delta=23^2-4*1*60
Delta=529-240
Delta= 289
x=(-b+-Sqr(Delta))/2*a
x1=(-23+17)/2
x1=-3
x2=(-23-17)/2
x2=-20
x1=-3 or x2= -20