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OpenStudy (anonymous):
Can someone explain how to find the inverse of a function like F(x)=1/3x+2
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OpenStudy (er.mohd.amir):
let y=1/(3x+2) (3x+2)y=1 3xy+2y=1 3xy=1-2y x=(1-2y)/3y
OpenStudy (er.mohd.amir):
that is inverse is=(1-2x)/3x
OpenStudy (anonymous):
How would I show they are inverses using function composition? Thanks for the help!!
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