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Algebra
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OpenStudy (anonymous):
4/√24x anyone help?
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OpenStudy (tanya123):
sqrt(2/3)/sqrt(x)
OpenStudy (mrnood):
@10404101 look at the equation this way... \[\frac{ 4 }{ \sqrt{24x}} =\frac{ \sqrt{16} }{ \sqrt{24} \sqrt{x} }\] OK? do you see haow that was done?
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