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Algebra 11 Online
OpenStudy (anonymous):

4/√24x anyone help?

OpenStudy (tanya123):

sqrt(2/3)/sqrt(x)

OpenStudy (mrnood):

@10404101 look at the equation this way... \[\frac{ 4 }{ \sqrt{24x}} =\frac{ \sqrt{16} }{ \sqrt{24} \sqrt{x} }\] OK? do you see haow that was done?

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