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Mathematics 21 Online
OpenStudy (kaliyah0524):

find XY

OpenStudy (kaliyah0524):

OpenStudy (unklerhaukus):

how many times greater is the area of the larger triangle?

OpenStudy (kaliyah0524):

21

OpenStudy (unklerhaukus):

no, not "how much greater?", "how many times greater"?

OpenStudy (kaliyah0524):

4

OpenStudy (unklerhaukus):

right, the larger triangle is four times greater. The sides will be: the square root the this; (√4) times the sides of the smaller tiranlge

OpenStudy (unklerhaukus):

*triangle

OpenStudy (kaliyah0524):

what?

OpenStudy (kaliyah0524):

the square root of that is 2.. then what

OpenStudy (unklerhaukus):

the ratio of the Sides of the triangles will equal to the square root of the ratio of the Areas

OpenStudy (unklerhaukus):

so the side of XYZ are all: 2 times the sides of DEF

OpenStudy (kaliyah0524):

so 24?

OpenStudy (unklerhaukus):

XY = 2 DE

OpenStudy (unklerhaukus):

|dw:1446786762195:dw|

OpenStudy (kaliyah0524):

..?

OpenStudy (unklerhaukus):

Find XY

OpenStudy (kaliyah0524):

it's not 24?

OpenStudy (unklerhaukus):

i don't know how you can get 24, it's way off.

OpenStudy (kaliyah0524):

are you sure? it's one of the answer choices ... How do I find XY

OpenStudy (kaliyah0524):

?

Directrix (directrix):

From above: XY = 2 DE XY = 2*4 4 is the given length of DE in the diagram XY = ?

OpenStudy (kaliyah0524):

6?

OpenStudy (unklerhaukus):

!!!!!!!

Directrix (directrix):

Two times 4 is not 6. Try again.

OpenStudy (kaliyah0524):

wow . blonde moment.. it's 8

Directrix (directrix):

Correct.

OpenStudy (kaliyah0524):

then what?

OpenStudy (kaliyah0524):

@Directrix

OpenStudy (kaliyah0524):

Neverming. But thanks both of you for the help

Directrix (directrix):

The posted question says to "find XY." XY= 8 so that's it. It is over.

Directrix (directrix):

You are welcome from us both.

OpenStudy (kaliyah0524):

Nevermind* & :)

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