Mathematics
21 Online
OpenStudy (kaliyah0524):
find XY
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OpenStudy (kaliyah0524):
OpenStudy (unklerhaukus):
how many times greater is the area of the larger triangle?
OpenStudy (kaliyah0524):
21
OpenStudy (unklerhaukus):
no, not "how much greater?", "how many times greater"?
OpenStudy (kaliyah0524):
4
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OpenStudy (unklerhaukus):
right, the larger triangle is four times greater.
The sides will be: the square root the this; (√4) times the sides of the smaller tiranlge
OpenStudy (unklerhaukus):
*triangle
OpenStudy (kaliyah0524):
what?
OpenStudy (kaliyah0524):
the square root of that is 2.. then what
OpenStudy (unklerhaukus):
the ratio of the Sides of the triangles
will equal to the square root of the ratio of the Areas
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OpenStudy (unklerhaukus):
so the side of XYZ are all: 2 times the sides of DEF
OpenStudy (kaliyah0524):
so 24?
OpenStudy (unklerhaukus):
XY = 2 DE
OpenStudy (unklerhaukus):
|dw:1446786762195:dw|
OpenStudy (kaliyah0524):
..?
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OpenStudy (unklerhaukus):
Find XY
OpenStudy (kaliyah0524):
it's not 24?
OpenStudy (unklerhaukus):
i don't know how you can get 24, it's way off.
OpenStudy (kaliyah0524):
are you sure? it's one of the answer choices ... How do I find XY
OpenStudy (kaliyah0524):
?
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Directrix (directrix):
From above:
XY = 2 DE
XY = 2*4 4 is the given length of DE in the diagram
XY = ?
OpenStudy (kaliyah0524):
6?
OpenStudy (unklerhaukus):
!!!!!!!
Directrix (directrix):
Two times 4 is not 6.
Try again.
OpenStudy (kaliyah0524):
wow . blonde moment.. it's 8
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Directrix (directrix):
Correct.
OpenStudy (kaliyah0524):
then what?
OpenStudy (kaliyah0524):
@Directrix
OpenStudy (kaliyah0524):
Neverming. But thanks both of you for the help
Directrix (directrix):
The posted question says to "find XY."
XY= 8 so that's it. It is over.
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Directrix (directrix):
You are welcome from us both.
OpenStudy (kaliyah0524):
Nevermind* & :)