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Algebra
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@gabbyalicorn
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multiply the binomial and trinomial: (x-5)(x^2+5x+25)
(x−5)(x^2+5x+25) =(x+−5)(x^2+5x+25) =(x)(x^2)+(x)(5x)+(x)(25)+(−5)(x^2)+(−5)(5x)+(−5)(25) =x3+5x^2+25x−5x^2−25x−125 =x^3−125
multiply the binomial (3x+8) (x-3)
3x+8)(x−3) =(3x+8)(x+−3) =(3x)(x)+(3x)(−3)+(8)(x)+(8)(−3) =3x^2−9x+8x−24 =3x^2−x−24
factor the following polynomial 12y^5-8y^3+24y^2
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12y^5−8y^3+24y^2 12y^5−8y^3+24y^2 =4y^2(3y^3−2y+6) Answer: 4y^2(3y^3−2y+6)
multiply 7z^3(2z^2-4z)
AFTER THIS QUESTION, PLEASE OPEN A NEW QUESTION :) THANK YOU <3 7z^3(2z^2−4z) =(7z^3)(2z^2+−4z) =(7z^3)(2z^2)+(7z^3)(−4z) =14z^5−28z^4
find the difference (7a^5+3a^2-5)-(7a^5+8a^2-2
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