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Mathematics 16 Online
OpenStudy (anonymous):

y'=x-2y

OpenStudy (irishboy123):

\(y' + 2y = x\) integrating factor \(e^{\int2dx}\)

OpenStudy (alekos):

have you worked it out yet?

OpenStudy (thomas5267):

To be honest, I would just use \(e^{-2x}\) because of that characteristic polynomial thingy. Then make a guess on the particular solution.

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