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help! WILL GIVE MEDALS!! i have no idea how to start this... find sin2x, cos2x, and tan2x given cscx=5, tanx<0
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tan x is positive in Q III
imm sorry, i put the wrong problem up
its supposed to be CSCx=5, tanx<0
ok then that angle is in the second quadrant csc x = 1/ sin x sin x = 1/5
ok, so then do i just do the formulas again, use cos2x and find sin2x?
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|dw:1446914844302:dw|
cos2a= \[1-2\sin ^{2}x\]
ohh wait so do the opposite over hypotenuse thing?
you can find cos x , tan x from the above digram
yes
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