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The absolute maximum value of
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\[y=\left| \sin^2 x+2sinx\right|\] on [0,2pi] is?
hint: the maximum value of sin(x) for \(0\le x \le 2\pi\) is 1. See following link for a graph. http://www.intmath.com/trigonometric-graphs/1-graphs-sine-cosine-amplitude.php
how do i solve this without graphing it?
What is |1+1|?
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