OpenStudy (zackattack350):

for the statement find the constant of variation and the variation equation. y varies jointly as x and the cube of z;y=24 when x=1 and z=2

1 year ago
OpenStudy (zackattack350):

@lochana

1 year ago
OpenStudy (lochana):

hmm.. okay. like they say in the question, y is given by sum of x , z^3 and some constant(say c). we get y = x + z^3 + c y= 24; x=1; z=2 24 = 1 + 2^3 + c c = 24 - 9 c = 15 constant = 15.

1 year ago
OpenStudy (zackattack350):

so if thats the constant using the equation at the top... how would i answer what the variation equation is? i have in the assignment y=(blank)xz^3

1 year ago
OpenStudy (lochana):

this is the best way that goes with your question. one can argue in many ways saying this is not to be true. but you can't find the constant if you go more deeper than my way. for example; one can ask , how do you exactly say coefficients of x , z is 1. that is not given. but I assume that to be 1. So this problem is not quite good one.:)

1 year ago
OpenStudy (zackattack350):

1 is a good assumption in my opinion. But i still have to answer what the equation is

1 year ago
OpenStudy (lochana):

but wait

1 year ago
OpenStudy (lochana):

I didn't get "jointly" here. After googling, I understood that jointly means multiplication.:) (english is not my native language) okay so y = cxz^3

1 year ago
OpenStudy (zackattack350):

oh! thank you i was confused about that as well.. Thanks for your help! ill tag you if i need you again :)

1 year ago
OpenStudy (lochana):

great

1 year ago