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OpenStudy (trantom):
do you remember the steps?
you need to get both the elements on the right side divisible by the elements on the left side
For this one, you can multiply P2O5 by 4 to get 4(P2O5)
Then put however many Ps and O2s you need on the left side
OpenStudy (phebe):
where the 4 came from?
OpenStudy (phebe):
2 times 2?
OpenStudy (trantom):
No, the 4 came from the fact that in order for the numbers on the right side to both be divisible by the numbers on the left side, you can multiply it by four.
It's officially called the LCM, the least common multiply
OpenStudy (trantom):
*multiple
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OpenStudy (phebe):
okay so then what do i do?
OpenStudy (phebe):
dont i multiply the 5 and 2
OpenStudy (trantom):
well now you have 4(P2O5) and you need to get that from P + O2
First, how many total Os do you have to get?
OpenStudy (phebe):
i got the answer now
THANK YOU!!
OpenStudy (trantom):
what did you get?
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