Question

8^(6+3x)=16

Answer 1

\[16=2^4\] is a start

Answer 2

and since \(8=2^3\) you have \[8^{6+3x}=\left(2^3\right)^{6+3x}\]

Answer 3

use the law of exponents to write \[(2^3)^{6+3x}=2^{18+9x}\]

Answer 4

got it! thank you!

Answer 5

yw