Question

How to solve
2x^2-12=-5x

Answer 1

Subtract -5x from both sides.
\[\huge~\rm~2x^2−12−−5x=−5x−−5x\]
\[\huge~\rm~ 2x^2+5x−12=0\]
From here we need to factor by grouping

\[\huge~\rm~ax^2+bx+c=0\]
\[\huge~\rm~ 2x^2+5x−12=0\]

Using the stander-ed form equation we determine what a and c are in this case they are
a=2
b=-12
When we multiply them together we get -24
B remains as 5

What numbers add up to 5 but multiply to make -24?