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Find the solution to the system of equations. x+y+z=8 y+z=5 z=2
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A. x = 3, y = 3, z = 1 B. x = 3, y = 3, z = 2 C. x = 8, y = 3, z = 2 D. x = 4, y = 3, z = 2
You are given the z, so substitute that into the other two equations.
x + y + 2 = 8 y + 2 = 5
It would be the A
Now, the solution for y comes in handy from the 2nd equation, and then substitute the solution for y into the 1st equation and solve for x.
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It is impossible to be A, because you already know that z=2 (not 1).
so it would be B @SolomonZelman ?
Yes, B is correct !
Ops wasn't paying attention I meant to say B thanks for the catch :)
Thanks !
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