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If cos2 x + 2cosx - 2 = 0, then cosx = _____. -1 ±√3 1 ±√3 ±√3 1
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Can you solve? \(\large\color{black}{ \displaystyle k^2+2k-2=0 }\)
You can do this: \(\large\color{black}{ \displaystyle k^2+2k-2=0 }\) \(\large\color{black}{ \displaystyle k^2+2k-2\color{red}{+3}=0 \color{red}{+3} }\) \(\large\color{black}{ \displaystyle k^2+2k+1=3 }\) \(\large\color{black}{ \displaystyle \left(k+1\right)^2=3 }\)
via «completing the square» method.
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