Question

An arithmetic sequence has the terms a6=53 and a8=61
A. What is the value of d? Whats the value of a1?
B. What is the explicit formula?
Thanks so much and could you maybe explain? :D

Answer 1

@Nnesha could you maybe possibly help? :3

Answer 2

you! ready ??

Answer 3

this is the formula for arithmetic sequence \[\huge\rm a_n = a_1 +(n-1)d\]
n= number of the terms we need
a_1 = first term
d= common difference

Answer 4

a_6 = 6th term =53
a_8 = 8th term = 61
so \[\rm when~~n=6~~~,a_n=a_6 =53\]
i'm going to replace n with 6 and a_6 with 53
\[\huge\rm a_\color{reD}{n} = a_1 +(\color{red}{n}-1)d\]\[\large\rm a_\color{reD}{6} = a_1 +(\color{red}{6}-1)d\]\[\large\rm \color{reD}{53} = a_1 +(\color{red}{5})d\]
^^^first equation

Answer 5

now write 2nd equation when a_8 = 61

and then subtract both e quations

Answer 6

ahh im sorry! i didn't know you came back on!! thanks so much tho !! :D

Answer 7

it's okay can you write 2nd equation give it a try