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OpenStudy (thread252):
here to help!
OpenStudy (ronlover101):
A container holds a combination of nickels and quarters. There are 156 coins in all, and their total value is $21.60. The system of equations models this situation, where x is the number of nickels and y is the number of quarters.
X+Y=156
0.05X+0.25Y=21.6
How many nickels and quarters are in the container?
A.
118 nickels and 38 quarters
B.
106 nickels and 50 quarters
C.
87 nickels and 69 quarters
D.
72 nickels and 84 quarters
OpenStudy (anonymous):
if you multiply the first equation by 0.05
OpenStudy (anonymous):
you get 0.05X+0.05Y=7.8
OpenStudy (thread252):
C
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OpenStudy (anonymous):
If you subtract the second equation by the first, you get...
0.2Y=13.8
OpenStudy (anonymous):
Y=69
OpenStudy (anonymous):
Plug in y into the first equation and you get
OpenStudy (anonymous):
X=87 so yes it is C
OpenStudy (thread252):
87 nickle and 69 quarter??????
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OpenStudy (ronlover101):
OK THANKS what about one more?
OpenStudy (anonymous):
Go for it
OpenStudy (ronlover101):
ok
OpenStudy (ronlover101):
6x + 4y = 2
3x + 2y = 1
A.
inconsistent
B.
consistent and independent
C.
coincident
D.
not enough information