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Mathematics 11 Online
OpenStudy (girlgoyleh.):

The perimeter of a rectangular sandbox is 60 ft. The length is two times the width. Find the length and the width of the sandbox.

OpenStudy (anonymous):

P=l*w so 60=x*2x

OpenStudy (anonymous):

or 60=3x so we divide by 3

OpenStudy (anonymous):

60/3=x 20=x l=2*20 =40 w=20

OpenStudy (solomonzelman):

length - \(\color{black}{\ell}\) width - \(\color{black}{w}\) perimeter - \(\color{black}{\rm P}\) \(\color{black}{{\rm P}=2(\ell+w)}\) \(\scriptsize\color{ #996600 }{\scriptsize{\bbox[5pt, #996600 ,border:2px solid #996600 ]{~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ }}}\) \(\color{black}{60=2(\ell+w)}\) \(\color{black}{\ell=2w}\) Solve this system of equations.

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