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Solve the following three rational equations. WILL MEDAL AND FAN!!!
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\[\frac{ 6 }{ x+12 } = \frac{ 10 }{ x-4 }\]
HI!! again
start with \[6(x-4)=10(x+12)\]
\[\frac{ x+12 }{ 6 } = \frac{ x-12 }{ 2 }\] and \[2=12+\frac{ 10 }{ x+10 }\]
second one just like the first
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That's 6x-24=10x+120
third one start with \[-10=\frac{10}{x+10}\]
yes you are right, solve \[ 6x-24=10x+120\]
-24=4x+120 -144=4x -36=x
2x+24=6x-72 96+2x=6x 96=4x 24=x
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-10x-100=10 -10x=110 x=-11
I guess I just needed help getting started. Thanks!!! :) <3
looks like you got it
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