May someone please help me? Thanks~! (2x-1)(-x^2+5x+5)
I know the answer ,but i need help on how to do it.
I can teach you two methods, the cross multiplication method, or the distributive method. Choose what you want to learn.
id like to learn both but first ill do the distributive method. :)
Thank you
In distributive method, say we have\[(a+b) (x+y+z) = ax+ay+az+bx+by+bz\]
wait so how do i use this with this equation?
all the steps but i dont understand it.
@Yttrium please help
Could we take this step by step? Tomorrow i have a test and I have to know this too.
Say we have your problem. (2x - 1) (-x^2+5x+5)
k
so first step look at the problem which in this case is (2x-1) (-x^2+5x+5) I understand that.
|dw:1447138834364:dw| this is the second step, you must distribute 2x to the other factor
wait wait wait why to second step?
That will make 2x (-x^2 +5x + 5)
i dont get it.
actually i do, so you take away the -1 after the 2x?
You said that the first step is to look at the problem. And what i said is the first step in the distributive method. I just broke it down
Yes, that is right.
k i get it so far
the same method will follow for -1
wait for the -1? We just got rid of it though.
So, initially, what we will be having is\[2x (-x^{2} + 5x + 5) - 1 (-x^{2}+5x +5)\]
We didn't remove -1 in our process, i just remove it for you to focus on the process itself. Do you understand me so far?
yea now i get it.
so we have to write (-x^2+5x+5) twice correct?
well it is because you wrote it but why?
We our doing "DISTRIBUTIVE METHOD". Our main objective here is to distribute each term of one of the factor to the whole another factor.
ok ok
so whats next?
|dw:1447139960975:dw| We well distribute 2x and -1 to each term of (-x^2+5x+5)
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