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Solve check 2/3/y = 6 A.1/9 B.1/4 C.9 D.4
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@CoolDude12
2/3 y = 6 multpky both sides by 3 2y=6*3 and divide both sides by 2 y = (6*3)/2 do the math then check by placing your answer back in the original eqaution
\[\frac{ 2 }{ 3}y \]
both sides of what?
the equal signs or equation
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so multiply \[\frac{ 2 }{ 3 }y\] = 6
if wee multiply both sides by 3 we get rid of the denominator of three on the left hand side
so 2y = 6*3
\[\frac{ 2 }{ 3 } \times \frac{ 6 }{ 3 }\]
\[(3)\frac{ 2 }{ 3 }y = 6(3)\]
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the threes cancel
we are left with\[2y = 6(3)\]
i think 9
well place nine back in original equation
\[\frac{ 2 }{ 3}\times9 = 6\]
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there is your check good job!!
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