Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (maddy1251):

Question regarding functions of a log graph? The function is y=log(x-2)+5 (just like that) How do you determine the range, domain, vertical asymptote of this type of function? I will post a picture of the graph for a visualization, I can kind of guess what the answers are but I need some guidance to help. Will fan and medal!

OpenStudy (maddy1251):

OpenStudy (freckles):

Domain of y=log(x) is x>0. Range of y=log(x) is all real numbers. Vertical asymptote of y=log(x) is x=0.

OpenStudy (freckles):

So let's used this for our problem.

OpenStudy (freckles):

Domain of y=log(x-2)+5 is x-2>0 <--solve Range of y=log(x-2)+5 is all real numbers Vertical asymptote of y=log(x-2)+5 is x-2=0 <--solve

OpenStudy (freckles):

hopefully you can also see this from the graph you posted

OpenStudy (freckles):

Notice for the x values the curve is only where? Notice for the y values the curve is where? Notice that your curve is getting closer to what vertical line?

OpenStudy (maddy1251):

@freckles I assumed that the curve had something to do with what was going to be my range, how it affected my domain, and the same for the vertical asymptote. Thank you so so much!

OpenStudy (freckles):

Np. So you have no questions on this problem?

OpenStudy (maddy1251):

@freckles Nope, you pretty much cleared all them up for me with your explanations. I hate asking questions on these but I have always struggled with log functions. Thankfully you all on here are very helpful, and I am slowly learning them better. My teacher isn't the greatest at teaching them.

OpenStudy (freckles):

Ok well... That was easy...:p

OpenStudy (freckles):

I mean explaining it...

OpenStudy (maddy1251):

@freckles Haha well it actually was easy doing it, as well. I was looking and see another problem similar to it, so I am going to take what you told me and apply it to the next function, I should get it :) See, you helped me with more than just one problem!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!