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Mathematics 22 Online
OpenStudy (maddy1251):

Solve for 'x' in the equation 300=200e^0.3x

imqwerty (imqwerty):

try dividing both sides by 200 then u take log on both sides with base e

OpenStudy (maddy1251):

@imqwerty \[1.5=e^{0.3x}\] Is that a good start

imqwerty (imqwerty):

yes

imqwerty (imqwerty):

are u allowed to use calculators?

OpenStudy (maddy1251):

Yes

imqwerty (imqwerty):

ok now try doing this- we take log with base e on both sides \[\log_{e}1.5=\log_{e}e^{0.3x}\]

OpenStudy (maddy1251):

Would that be like taking log 1.5? @imqwerty

imqwerty (imqwerty):

can u tell what is the base of logarithm in this^

OpenStudy (maddy1251):

Well it has base 'e' right?

imqwerty (imqwerty):

yes we are taking base e we take base as e in this case so that the right hand side of the equation can be simplified easily :)

imqwerty (imqwerty):

if u get confused somewhere feel free to ask

OpenStudy (maddy1251):

@imqwerty is the answer bout 1.35?

imqwerty (imqwerty):

yeah its 1.35

OpenStudy (maddy1251):

Okay awesome! For \[1500=25 \times 2^{0.45x}=23.58?\]

OpenStudy (maddy1251):

Approx. that is.

imqwerty (imqwerty):

try doin it again :) i think theres a lil mistake

imqwerty (imqwerty):

to check your answers ...to see if they are correct u jst try putting the value of x that ur getting into the equation :) liek here u got x=23.58 approx when u put it in the equation 25x2^{0.45x} 25x 2^{0.45x23.58} =39099.328 so this is not 1500 therefore x=23.58 is wrong

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