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imqwerty (imqwerty):
try dividing both sides by 200
then u take log on both sides with base e
OpenStudy (maddy1251):
@imqwerty \[1.5=e^{0.3x}\] Is that a good start
imqwerty (imqwerty):
yes
imqwerty (imqwerty):
are u allowed to use calculators?
OpenStudy (maddy1251):
Yes
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imqwerty (imqwerty):
ok now try doing this-
we take log with base e on both sides
\[\log_{e}1.5=\log_{e}e^{0.3x}\]
OpenStudy (maddy1251):
Would that be like taking log 1.5? @imqwerty
imqwerty (imqwerty):
can u tell what is the base of logarithm in this^
OpenStudy (maddy1251):
Well it has base 'e' right?
imqwerty (imqwerty):
yes we are taking base e
we take base as e in this case so that the right hand side of the equation can be simplified easily :)
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imqwerty (imqwerty):
if u get confused somewhere feel free to ask
OpenStudy (maddy1251):
@imqwerty is the answer bout 1.35?
imqwerty (imqwerty):
yeah its 1.35
OpenStudy (maddy1251):
Okay awesome! For \[1500=25 \times 2^{0.45x}=23.58?\]
OpenStudy (maddy1251):
Approx. that is.
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imqwerty (imqwerty):
try doin it again :)
i think theres a lil mistake
imqwerty (imqwerty):
to check your answers ...to see if they are correct u jst try putting the value of x that ur getting into the equation :)
liek here u got x=23.58 approx
when u put it in the equation
25x2^{0.45x}
25x 2^{0.45x23.58}
=39099.328
so this is not 1500 therefore x=23.58 is wrong