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factoring question 16n(^2) -9 so far I've pulled out a 3 3(6n(^2) - 3) I'm not sure where to go from here...
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you think 3 x 6 is 16?
what does it look like \[16n^2-9\]
oh god my bad
or \[(16n)^2-9\] maybe
the first one
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(4n-3)(4n-3) ?
have you seen this before \[a^2*x^2-b^2 = (ax-b)*(ax+b)\]
*(4n+3)
right, you can check by distributing back and see if you return to the original prob
you have 4^2*n^2 - 3^2 apply that property above..
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