Question

Factor our the common factor first.
A. 2n^2 - 16 = 0
B. 7n^2 - 21 = 0

Answer 1

A
What is a common factor of 2 and 16? (greatest)

Answer 2

2

Answer 3

Ok so now when we divide both if the numbers by 2 what are we left with?

Answer 4

n^2 - 8 = 0

Answer 5

hm, na thats what im stuck on

Answer 6

Wait i messed up sorry >.<

Answer 7

oh lol , no problem

Answer 8

You have the common factor correct
But before the we need to add 16 to both sides

Answer 9

oh, okay

Answer 10

2n^2 = 16

Answer 11

\[\huge~\rm~2n^2 - 16+16 = 0+16\]
\[\huge~\rm~2n^2 =16\]

Answer 12

yep

Answer 13

Now we divide both sides by 2

Answer 14

n^2 = 8

Answer 15

\[\huge~\rm~\sqrt{n^2} = \sqrt{8}\]

Answer 16

aight now i have to find the square root of 8

Answer 17

There is no square root of 8...

Answer 18

What exactly is your question??

Answer 19

Refer to the last prob i helped with, same to solve after factoring

Answer 20

ohhkay, nvm thanks

Answer 21

remember this thing \[\sqrt{x^2}=\left| x \right|\]

Answer 22

yeah

Answer 23

and the other side is root of 8,
and so
x can be + or - root of 8

Answer 24

alright thanks

Answer 25

only difference is they want you to factor first, then divide and solve.. instead of just moving the 16 over and dividing by 2, then root everything,

Answer 26

same thing really,

you are multiplying the left by 2/2 or 1, which does not change it

Answer 27

(2/2) * (2n^2 - 16) = 0

Answer 28

you left the top 2 out front, and divided each term by 2, (multiply by 1/2) to get that factored form ..

Answer 29

ohh, okay thanks man

Answer 30

welcome, i hope ya see er clearly

Answer 31

yep i got it

Answer 32

the factored form is then

2*(n^2 - 8) = 0

that is all they want you to show, then solve normally, divide by 2, add 8, root

Answer 33

yep , gotcha thanks a lot man