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Please help! Verify the identity. 4 csc 2x = 2 csc2x tan x
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@Nnesha @jango_IN_DTOWN ???
Can you help me solve this??
wait a bit
Okay, thank you.
is it \[4\csc 2x=2\csc ^2xtanx \]
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\[4\csc 2x=\frac{ 4 }{ \sin 2x}=\frac{ 4 }{ 2\sin x \cos x }\]
\[4 \csc 2x = 2 \csc^2x \tan x\]
\[=2\csc x\frac{ \sin x }{\cos x }\frac{ 1 }{ \sin x }\]
\[=2\csc^2xtan x\]
Can you explain how you got that answer.
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I multiplies numerator and denominator by sin x and 1/sin x =csc x and sin x/cos x=tan x
*multiplied
sin 2x=2 sin x cos x
Thanks a million again!! @jango_IN_DTOWN
write the reasons wherever you use other identities.. The teacher will be happy too.:)
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